4(2-[3(c+1)-2(c+1)])=-2

Solution for 4(2-[3(c+1)-2(c+1)])=-2 equation:

Simplifying
4(2 + -1[3(c + 1) + -2(c + 1)]) = -2

Reorder the terms:
4(2 + -1[3(1 + c) + -2(c + 1)]) = -2
4(2 + -1[(1 * 3 + c * 3) + -2(c + 1)]) = -2
4(2 + -1[(3 + 3c) + -2(c + 1)]) = -2

Reorder the terms:
4(2 + -1[3 + 3c + -2(1 + c)]) = -2
4(2 + -1[3 + 3c + (1 * -2 + c * -2)]) = -2
4(2 + -1[3 + 3c + (-2 + -2c)]) = -2

Reorder the terms:
4(2 + -1[3 + -2 + 3c + -2c]) = -2

Combine like terms: 3 + -2 = 1
4(2 + -1[1 + 3c + -2c]) = -2

Combine like terms: 3c + -2c = 1c
4(2 + -1[1 + 1c]) = -2
4(2 + [1 * -1 + 1c * -1]) = -2
4(2 + [-1 + -1c]) = -2

Combine like terms: 2 + -1 = 1
4(1 + -1c) = -2
(1 * 4 + -1c * 4) = -2
(4 + -4c) = -2

Solving
4 + -4c = -2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -4c = -2 + -4

Combine like terms: 4 + -4 = 0
0 + -4c = -2 + -4
-4c = -2 + -4

Combine like terms: -2 + -4 = -6
-4c = -6

Divide each side by '-4'.
c = 1.5

Simplifying
c = 1.5